Write 𝑥²+6𝑥+11 in the form (𝑥+a)²+b.

This question wants you to "complete the square". To start this question we put a = (coefficient of x)/2 = 6/2 = 3.So far we have 𝑥²+6𝑥+11 = (𝑥+3)²+b. We now need to find b. We can expand and simplify the right hand side to get 𝑥²+6𝑥+11 = 𝑥²+6𝑥+9+b. We should now be able to see that b=2. So 𝑥²+6𝑥+11 = (𝑥+3)²+2.