How do I solve inequalities when they're not linear?

Ok, let's talk about quadratic inequalities in particular. Look at the inequality x^2 - 8x + 15 > 0.What does a solution to this mean? It means the curve x^2 - 8x + 15 > 0 is above the x-axis at this point. So let's start by finding where the curve actually intersects the x-axis. That is, solutions to x^2 - 8x + 15 = 0.We know how to do this: just factorise. We get (x-5)(x-3) = 0, so the curve intersects the axis at x = 5 and at x = 3.Now, if you think about the shape of the curve, you will see that it is a parabola with a minimum and no maximum, since the x^2 term is positive. So in fact it must be that the curve is below the x-axis between x = 3 and x = 5, and above the axis everywhere else.So the solution to the inequality is x < 3 or x > 5.

DF

Related Maths GCSE answers

All answers ▸

Simplify completely: 3x^2 - 14x +5 /2x^2 -10x


Solve the following simultaneous equation: 1) 2x=y-5, 2) 2y^2=4x^2+4x-15


Solve 5x^2 = 10x + 4 Give your answers to 2 decimal places. [4 marks]


How do I expand (x-2)(3x+3) into a quadratic?