MYTUTOR SUBJECT ANSWERS

1545 views

How do I draw a straight line graph given a y=mx+c equation by the table method?

The y=mx+c equation is for a straight line (also known as 'linear') graph.

The 'y' is representative of the y-value, 'm' represents the gradient (how steep the graph is) and 'c' represents the y-intercept (where the graph cuts the y-axis).

To do this by the table method, lets take the following example:

Qu: Draw the graph of y=3x+4 for values of x between -3 and 3

We would draw a table as follows:

x:    -3   -2   -1   0   1   2    3      

3x:  -9   -6   -3   0   3   6    9

+4: +4  +4  +4  +4 +4  +4  +4

y:    -5   -2   -1   4   7  10   13

The first thing you do is write down the x-values for which the graph needs to be drawn (as specified in the qu, these are between -3 and 3)

You then put the 'mx' part of the equation in the next row. In our equation, m has the value of 3, so you write 3x (which algrebraically means 3 multiplied by x). Therefore, you multiple each x-value by 3, e.g -3x3=-9, -2x3=-6 etc. and write these values in.

You then put the +c part of the equation in the row below. In our equation, c has the value of 4, so you put +4 along the whole row. 

You then work out the y-value by adding the 2 rows above. Eg. For the value of x=-3, y=-9+4 which is equal to -5. Therefore, when x is -3, y is -5 - the coordinates would be (-3, -5). You do this for every value, which will give you a series of coordinates. 

You can then plot these coordinates on a graph and join them up to form your line graph!

 
Neha C. A Level Biology tutor, GCSE Maths tutor, GCSE Biology tutor

3 years ago

Answered by Neha, a GCSE Maths tutor with MyTutor


Still stuck? Get one-to-one help from a personally interviewed subject specialist

781 SUBJECT SPECIALISTS

£22 /hr

Eleanor H.

Degree: Biochemistry (Bachelors) - Bristol University

Subjects offered:Maths, Chemistry+ 1 more

Maths
Chemistry
Biology

“ABOUT ME: I am a biochemistry student, currently studying at the University of Bristol, and have had a passion for the natural sciences from a very young age. I am patient, hardworking and experienced, having tutored students in Maths...”

£30 /hr

Anuradha D.

Degree: Physics (Masters) - Durham University

Subjects offered:Maths, Physics+ 4 more

Maths
Physics
Music
Further Mathematics
Chemistry
-Personal Statements-

“Hello everyone! My name is Anuradha (you can call me Anu), and I am a Physics Undergrad at Durham. I have always had a “thing” for science and am so pleased to be studying it – and hope that I can give you all the support you need to ...”

£18 /hr

Pankaj K.

Degree: Physics (Bachelors) - Kings, London University

Subjects offered:Maths, Physics+ 1 more

Maths
Physics
Further Mathematics

“Positive, Dedicated, Motivating, Calm, Patient, Understanding, Professional, Organised, Experienced, Focused, Enthusiastic, Passionate”

MyTutor guarantee

About the author

£24 /hr

Neha C.

Degree: Medicine (Bachelors) - Birmingham University

Subjects offered:Maths, Biology

Maths
Biology

“Passionate, patient and pleasant tutor, tutoring students on maths and science subjects.”

You may also like...

Other GCSE Maths questions

expand and simplify (x+3)(x-7)

If f(x)=8x-3, what is the inverse function?

Find ∫(4x - 2/(x^3)) dx

Factorise x^2+2x-8

View GCSE Maths tutors

We use cookies to improve your site experience. By continuing to use this website, we'll assume that you're OK with this. Dismiss

mtw:mercury1:status:ok