How do I draw a straight line graph given a y=mx+c equation by the table method?

The y=mx+c equation is for a straight line (also known as 'linear') graph.

The 'y' is representative of the y-value, 'm' represents the gradient (how steep the graph is) and 'c' represents the y-intercept (where the graph cuts the y-axis).

To do this by the table method, lets take the following example:

Qu: Draw the graph of y=3x+4 for values of x between -3 and 3

We would draw a table as follows:

x:    -3   -2   -1   0   1   2    3      

3x:  -9   -6   -3   0   3   6    9

+4: +4  +4  +4  +4 +4  +4  +4

y:    -5   -2   -1   4   7  10   13

The first thing you do is write down the x-values for which the graph needs to be drawn (as specified in the qu, these are between -3 and 3)

You then put the 'mx' part of the equation in the next row. In our equation, m has the value of 3, so you write 3x (which algrebraically means 3 multiplied by x). Therefore, you multiple each x-value by 3, e.g -3x3=-9, -2x3=-6 etc. and write these values in.

You then put the +c part of the equation in the row below. In our equation, c has the value of 4, so you put +4 along the whole row. 

You then work out the y-value by adding the 2 rows above. Eg. For the value of x=-3, y=-9+4 which is equal to -5. Therefore, when x is -3, y is -5 - the coordinates would be (-3, -5). You do this for every value, which will give you a series of coordinates. 

You can then plot these coordinates on a graph and join them up to form your line graph!

Neha C. A Level Biology tutor, GCSE Maths tutor, GCSE Biology tutor

2 years ago

Answered by Neha, a GCSE Maths tutor with MyTutor

Still stuck? Get one-to-one help from a personally interviewed subject specialist


Samuel H. A Level Maths tutor, A Level Physics tutor, GCSE Maths tuto...
View profile
£20 /hr

Samuel H.

Degree: Mathematics with International Study (Masters) - Exeter University

Subjects offered: Maths, Physics


“I have not only been able to teach AS Level students how to solve mechanics problems; I helped them understand the concepts behind the problems”

Harry M. GCSE Maths tutor, A Level Maths tutor, GCSE Physics tutor, A...
View profile
£18 /hr

Harry M.

Degree: Physics (Masters) - Exeter University

Subjects offered: Maths, Physics


“Hey everyone,If you're reading this, then I assume you're stuck on something physics-y or maths-y. If so, thenI can help! I'm a Physics student at Exeter University and I can be your guru. Physics reduces the complex world to somethi...”

PremiumRebecca V. A Level Maths tutor, 13 plus  Maths tutor, GCSE Maths tuto...
View profile
£18 /hr

Rebecca V.

Degree: MA Logic and Philosophy of Mathematics (Masters) - Bristol University

Subjects offered: Maths, Physics+ 1 more

Further Mathematics

“Hi, I'm Rebecca, I'm 23 and I'm currently taking a year to myself just to study, doing my masters in Logic and Philosophy of Maths. To me, mathematics has always been black and white, right or wrong whilst philosophy is all about thin...”

About the author

PremiumNeha C. A Level Biology tutor, GCSE Maths tutor, GCSE Biology tutor
View profile
£22 /hr

Neha C.

Degree: Medicine (Bachelors) - Birmingham University

Subjects offered: Maths, Biology


“Passionate, patient and pleasant tutor, tutoring students on maths and science subjects.”

You may also like...

Other GCSE Maths questions

How do you solve this problem?

simplify (x-1)^2 - (x-1)

Find the exact value of the gradient of the curve y=e^(2-x)ln(3x-2) at the point on the curve where x=2.

How do I factorise x^2 + 8x + 15?

View GCSE Maths tutors


We use cookies to improve our service. By continuing to use this website, we'll assume that you're OK with this. Dismiss