How do I draw a straight line graph given a y=mx+c equation by the table method?

The y=mx+c equation is for a straight line (also known as 'linear') graph.

The 'y' is representative of the y-value, 'm' represents the gradient (how steep the graph is) and 'c' represents the y-intercept (where the graph cuts the y-axis).

To do this by the table method, lets take the following example:

Qu: Draw the graph of y=3x+4 for values of x between -3 and 3

We would draw a table as follows:

x:    -3   -2   -1   0   1   2    3      

3x:  -9   -6   -3   0   3   6    9

+4: +4  +4  +4  +4 +4  +4  +4

y:    -5   -2   -1   4   7  10   13

The first thing you do is write down the x-values for which the graph needs to be drawn (as specified in the qu, these are between -3 and 3)

You then put the 'mx' part of the equation in the next row. In our equation, m has the value of 3, so you write 3x (which algrebraically means 3 multiplied by x). Therefore, you multiple each x-value by 3, e.g -3x3=-9, -2x3=-6 etc. and write these values in.

You then put the +c part of the equation in the row below. In our equation, c has the value of 4, so you put +4 along the whole row. 

You then work out the y-value by adding the 2 rows above. Eg. For the value of x=-3, y=-9+4 which is equal to -5. Therefore, when x is -3, y is -5 - the coordinates would be (-3, -5). You do this for every value, which will give you a series of coordinates. 

You can then plot these coordinates on a graph and join them up to form your line graph!

 

NC
Answered by Neha C. Maths tutor

13764 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

simplify 7(3y-5) - 2(10 + 4y)


Work out an estimate for the value of (8.1 x 198)/0.0491


What are the solutions to x^2+3x+2=0


A circular table top has diameter 140 cm. The volume of the table top is 17,150π cmᶟ. Calculate the thickness of the table top


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning