Integrate the function : F'(x)=3x^2+4x-5

F'(x)=3x^2+4x-5
F(x)=(3/(2+1))(x^(2+1))+(4/(1+1)) (x^(1+1))-5(x^(0+1))

Answer: F(x)=x^3+2x^2-5x+c