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Integrate the function : F'(x)=3x^2+4x-5

F'(x)=3x^2+4x-5
F(x)=(3/(2+1))(x^(2+1))+(4/(1+1)) (x^(1+1))-5(x^(0+1))

Answer: F(x)=x^3+2x^2-5x+c

Answered by Ian Malique D. • Maths tutor

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