The numbers a, b, c and d satisfy the following equations: a + b + 3c + 4d = k; 5a = 3b = 2c = d. What is the smallest value for k for which a, b, c and d are all positive integers
- 5a = 3b = 2c = d. d must be a multiple of 5, 3 and 2, therefore the smallest possible value for d is 30. This sets a = 6, b = 10 and c = 152) a + b + 3c + 4d = 6 + 10 + 3x15 + 4x30 = 181 k = 181
MH
Related Maths A Level answers
All answers ▸Given that d/dx(cosx)=-sinx show that d/dx(secx)=secx(tanx)
Using the trigonometric identity for tan(A + B), prove that tan(3x)=(3tan(x)-tan^3(x))/(1-3tan^2(x))
Express (3 + 13x - 6x^2)/(2x-3) in the form Ax + B + C/(2x - 3)
How can I get better at Mathematics? I am struggling with confidence and achieving low grades.