Solve: a) 5t + 17 = 2. b) x^3 - 25 = 103 - x^3.

a) 5t + 17 = 2. We want to work out what t is. t = ?.To do this we need to get t on it's own, so first we move all the other numbers to equal t.We do this by subtracting 17 from both sides and we should find that 5t = -15.Now we have 5t but we need to divide both sides by 5 to get just the value of t, so since -15/5 = -3... t = -3.b) x3- 25 = 103 - x3. The same applies here, we want to find the value of x.So first we get all the x's on one side: 2x3 = 128Then we can half the value on both sides to find that x3 = 64.Now we need to get rid of the cube on the x, so must find the cube root of both sides. The cube root of 64 is 4. So x = 4.

JA

Related Maths GCSE answers

All answers ▸

Expand (x+1)(x-4)


Solve 2x^2 + 6x + 4 = 0 for x using the quadratic formula.


The equation of line L1 is y=3x-5. The equation of line L2 is 2y-6x+5=0. Show that these two lines are parallel.


Three positive whole numbers have a mean of 6. What is the greatest possible range of the three numbers?