Using the substitution method, solve the following simultaneous equations 2y+3x=14 and 6x-y=8

Equation 1: 2y+3x=14 Equation 2: 6x-y=8 Rearrange Equation 2: y=6x-8 therefore 2y=12x-16 Substituting the rearranged equation 2 into equation 1: 12x-16+3x=14 15x-16=14 15x=30 x=2 Substituting x into equation 2: 6(2)-y=8 12-y=8 y=12-8 y=4 and check at the end to make sure!

AW
Answered by Alex W. Maths tutor

3412 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How do I complete the square?


How do I rearrange and make y the subject in equations such as "(y/4) - X = 1"?


Simplify the following: ((1/3)(c^2))^3


8x – 7 > 6x + 12


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning