Using the product rule, differentiate: y = (x^2 - 1)(x^3 + 3).
y=(x2-1)(x3+3) let u=x2-1 u'=2x let v=x3+3 v'=3x2 uv'+u'v=(x2-1)(3x2)+(2x)(x3+3) =(3x4-3x2)+(2x4+6X) =5x4-3x2+6x
Related Maths A Level answers
All answers ▸I always mix up my integration and differentiation. How do i stop this?
Given x = 3sin(y/2), find dy/dx in terms of x, simplifying your answer.
What is the difference between mutually exclusive and indepedent events?
How do you solve a quadratic inequality eg find the values of x for which x^2 -6x +2 < -3