Using the product rule, differentiate: y = (x^2 - 1)(x^3 + 3).

y=(x2-1)(x3+3) let u=x2-1 u'=2x let v=x3+3 v'=3x2 uv'+u'v=(x2-1)(3x2)+(2x)(x3+3) =(3x4-3x2)+(2x4+6X) =5x4-3x2+6x

Answered by Maths tutor

3270 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How do you integrate ln(x)?


Given that the binomial expansion of (1+kx)^n begins 1+8x+16x^2+... a) find k and n b) for what x is this expansion valid?


Solve the following equation by completing the square: x^2 + 6x + 3 = 0.


What does it mean to differentiate a function?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences