The curve C has equation ye^(-2x) = 2x + y^2. Find dy/dx in terms of x and y.

The curve's equation is presented as an implicit function. Therefore we must use implicit differentiation to solve this problem. To do this, we differentiate both sides of the equation with respect to x, applying the chain rule where a y variable appears, and then rearrange to give dy/dx. The equation given in the question differentiates implicitly to e-2x(dy/dx) - 2ye-2x = 2 + 2y(dy/dx). This can be rearranged to dy/dx = (2 + 2ye-2x )/ (e-2x- 2y)

GW
Answered by Georgia W. Maths tutor

8751 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

The Curve, C, has equation: x^2 - 3xy - 4y^2 +64 =0 Find dy/dx in terms of x and y. [Taken from Edexcel C4 2015 Q6a]


Find the intersection coordinates of both axis with the function: f(x)=x^2-3x+4/3


What is the equation of the tangent to the curve y=x^3+3x^2+2 when x=2


How do you differentiate using the chain rule?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning