Solve algebraically the simultaneous equations: 6m + n = 16 and 5m - 2n = 19

The first step of solving simultaneous equations with two unknown variables (m & n in this case) is to rearrange one of the equations so that we get one variable in terms of the other. Lets take the first equation. We can rearrange this to n = 16 - 6m by subtracting 6m from both sides of the equal sign. Now we can substitute this value of n into the second equation, creating 5m - 2 * ( 16 - 6m ) = 19. We now have an equation which is entirely in terms of m, so we can simplify this down by multiplication and subtraction to 5m - 32 + 12m = 19 and then to 17m = 51. If we divide both sides by 17, we get m = 3. Substituting this value of m into the first equation gives 6 * 3 + n = 16, which simplifies to n = -2 by similar arithmetic.

HD
Answered by Harry D. Maths tutor

4642 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the simultaneous equations: 3x+5y=3 and 6x+6y=10


Two shops have deals for purchasing pens: "3 for £2" and "5 for £3" . Mr. Papadopoulos wants to buy 30 pens for his class in school, which deal should he use if he wants to spend the least amount of money possible, and how much will he spend?


Solve the equations giving your answer in 2d.p (5 Marks).: x^2 + y^2 = 36 , x = 2y + 6


X is a prime number higher than the square of 5 and lower than the square of 7. What are the smallest and largest possible values for X?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning