Describe the process of oxygen transport via haemoglobin.

Haemoglobin is a complex metal ion consisting of hexa-coordinated Fe2+ ions. With 6 coordinate bonds, haemoglobin forms an octahedral shape where 4 nitrogen ligands form a haem disc, a globin molecule forms the 5th bond, and the final bond can be interchanged between H2O and O2. An equilibrium is established by this 6th bond, following the equation: Hb(H2O)4 + 4O2 <=> Hb(O4) + 4H2O. In the lungs, oxygen concentration is higher, or increased, so equilibrium shifts right to oppose the change, meaning the H2O ligands are substituted for O2 ligands to form oxyhaemoglobin to carry oxygen through the blood. As the oxyhaemoglobin arrives at respiring tissues, oxygen concentration is low, while water concentration is higher due to respiration. Equilibrium shifts left to oppose the change, and oxygen is exchanged with water molecules. When haemoglobin reaches the lungs again, the process repeats.

Answered by Chemistry tutor

4172 Views

See similar Chemistry A Level tutors

Related Chemistry A Level answers

All answers ▸

Define enthalpy of neutralisation and state standard conditions:


Describe a 2 step synthesis to form pentan-1-ol from pentane.


What is a rate of reaction? How can we calculate the rate of reaction?


Calculate the standard enthalpy of combustion of a methane sample by using the standard enthalpies of formation.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences