A compound is found to contain 37.21% carbon, 7.75% hydrogen and 55.04% chlorine. What is it's empirical formula?
Carbon: 37.21/12= 3.1Hydrogen:7.75/1=7.75Chlorine: 55.04/35.5=1.55Ratio:c:H:Cl3.1:7.75:1.552:5:1Therefore empirical formula= C2 H5Cl
LP
Carbon: 37.21/12= 3.1Hydrogen:7.75/1=7.75Chlorine: 55.04/35.5=1.55Ratio:c:H:Cl3.1:7.75:1.552:5:1Therefore empirical formula= C2 H5Cl
