Given that the graph f(x) passes through the point (2,3) and that f'(x)=6x^2-14x+3, find f(x).

For this question we already have the derivative of f(x), and so if we integrate it we should get to a general equation with a constant on the end, however we want to get to an exact solution which we should be able to get to by plugging the point into f(x). So it f'(x) = 6x2-14x+3 then f(x) = 6x3/3 - 14x2/2 + 3x/1 + C = 2x3 - 7x2 + 3x + C. So now we have to plug x =2 and f(x) = 3 into this and get 3 = 2 x 8 - 7 x 4 +3 x 2 + C => C = 9. Therefore f(x) = 2x3 - 7x2 + 3x + 9

Answered by Maths tutor

4636 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Prove the identity: (sinx - tanx)(cosx - cotx) = (sinx - 1)(cosx - 1)


Integrate x((x^2)+2) dx


The equation of a curve C is (x+3)(y-4)=x^2+y^2. Find dy/dx in terms of x and y


A quantity N is increasing with respect to time, t. It is increasing in such a way that N = ae^(bt) where a and b are constants. Given when t = 0, N = 20, and t = 8, N = 60, find the value: of a and b, and of dN/dt when t = 12


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning