The gradient of a curve is given by dy/dx = 6sqrt(x) + 2. The curve passes through the point (16, 38). Find the equation of the curve.

dy/dx = 6x1/2 + 2 y = (62/3)x3/2 + 2x + c = 4x3/2 + 2x + c 38 = (4163/2) + (2*16) + c c = 38 - 256 - 32 = -250 y = 4x3/2 + 2x - 250

FW
Answered by Fraser W. Maths tutor

5023 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

What is the gradient of the quadratic function y=3x²?


The line L has equation 7x - 2y + 11 = 0, Find the gradient of l


if a^x= b^y = (ab)^(xy) prove that x+y =1


How would you differentiate f(x)=3x(2x-1)^2


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning