The gradient of a curve is given by dy/dx = 6sqrt(x) + 2. The curve passes through the point (16, 38). Find the equation of the curve.

dy/dx = 6x1/2 + 2 y = (62/3)x3/2 + 2x + c = 4x3/2 + 2x + c 38 = (4163/2) + (2*16) + c c = 38 - 256 - 32 = -250 y = 4x3/2 + 2x - 250

FW
Answered by Fraser W. Maths tutor

4554 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find the integral of 1/(x-5) with respect to x


Solve the simultaneous equation x+y=11(1), x^2+y^2=61 (2)


A curve has equation (x+y)^2=x*y^2, find the gradient of the curve at a point where x=1


What is Integration


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences