Find all of the roots of the equation y = 3x^3 - 12x

Step 1: Remove the most obvious factor, in this case 3x. y = 3x (x2 - 4) Step 2: Realize (x2 - 4) is the product of two squares and can undergo completing the square to produce two factors. y = 3x (x-2) (x+2) Step 3: Set each factor to equal 0 then rearrange to find the x value, as when the curve crosses the x-axis the value for the y component will be 0 and therefore at each root one of the factors will be equal to 0. 3x = 0, so x = 0. x-2 = 0, so x = 2. x+2 = 0, so x = -2. Therefore the roots are at (-2,0), (0,0) and (2,0)

VD
Answered by Victoria D. Maths tutor

3842 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Show that (2x^2 + x -15)/(2x^3 +6x^2) * 6x^3/(2x^2 - 11x + 15) simplifies to ax/(x + b) where a and b are integers


Solve algebraically for a and b: 6a+b=16, 5a-2b=19


Work out the value of 2^14 ÷ (2^9)^2


Two points P(–4, –1) and Q(–8, 5) are joined by a straight line. Work out the coordinates of the midpoint of the line PQ.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning