An industry is producing copper sulphate (CuSO4) from copper carbonate (CuCO3) and sulphuric acid (H2SO4). The company calculated that from 800 g of CuCO3 they will produce 1kg of CuSO4. However they only produced 900g. What is the percentage yield ?

The percentage yield is calculated in the following way: (Actual yield/Theoretical yield)*100 Here, the actual yield is 900g and the theoretical yield that the company calculated is 1kg. First , we have to convert the units of kg to g to be able to calculate.1kg=1000g Therefore, the percentage yield is: (900/1000)*100=90%

Answered by Dora L. Chemistry tutor

1450 Views

See similar Chemistry GCSE tutors

Related Chemistry GCSE answers

All answers ▸

Explain the physical properties of graphite in terms of its structure and bonding


What is ionic bonding and covalent bonding?


Given the balanced equation: MgCO3 + 2HCl --> MgCl2 + H2O + CO2, if 5 grams of MgCO3 is used, what volume of CO2 is produced? (molar mass of MgCO3 is 84.3 g/mol)


Why does the temperature decrease in the endothermic reaction?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy