Prove by contradiction that there is an infinite number of prime numbers.

The 'by contradiction' tells us we need to assume the opposite to begin with: 1) Let's assume there is a finite number of prime numbers2) Let P be the largest prime number (the last one) 3) if we multiply all the prime numbers up to and including P: 2x3x5x7...xP=q (the multiple of all prime number up to and including P)4) consider q+1 5) Will it be divisible by any prime P or less? no, as q is divisible by those and q+1 is only 1 more.6) So this means that either q+1 is Prime, or it has a prime factor larger than P.7) But P is the largest prime factor - this is a contradiction as there must exist a prime larger than PHence there is an infinite number of prime numbers

CL
Answered by Charlotte L. Maths tutor

18780 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

f(x)=ln(3x+1), x>0 and g(x)=d/dx(f(x)), x>0, find expressions for f^-1 and g


Find the equation of the normal to the curve at the point (1, -1 ): 10yx^2 + 6x - 2y + 3 = x^3


Where does the circle (x-6)^2+(y-7)^2=4 intersect with y=x+3


Using logarithms solve 8^(2x+1) = 24 (to 3dp)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning