Prove by contradiction that there is an infinite number of prime numbers.

The 'by contradiction' tells us we need to assume the opposite to begin with: 1) Let's assume there is a finite number of prime numbers2) Let P be the largest prime number (the last one) 3) if we multiply all the prime numbers up to and including P: 2x3x5x7...xP=q (the multiple of all prime number up to and including P)4) consider q+1 5) Will it be divisible by any prime P or less? no, as q is divisible by those and q+1 is only 1 more.6) So this means that either q+1 is Prime, or it has a prime factor larger than P.7) But P is the largest prime factor - this is a contradiction as there must exist a prime larger than PHence there is an infinite number of prime numbers

CL
Answered by Charlotte L. Maths tutor

18788 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How do I sketch a polynomial function?


A sweet is modelled as a sphere of radius 10mm and is sucked. After five minutes, the radius has decreased to 7mm. The rate of decrease of the radius is inversely proportional to the square of the radius. How long does it take for the sweet to dissolve?


A curve has equation y = f(x) and passes through the point (4,22). Given that f'(x) = 3x^2 - 3x^(1/2) - 7 use intergration to find f(x).


Express [1+4(square root)7] /[ 5+ 2(square root)7] in the form m + n (square root)7 , where m and n are integers.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning