A linear sequence starts with: a + 2b ; a + 6b ; a + 10b etc. The 2nd term has value 8. The 5th term has value 44. Work out the values of a and b.
We know that the 2nd term has a value of 8. Thus a + 6b = 8;What is more, we also know that the 5th term has a value of 44. We also know that the next element in the sequence increases by 4b when compared to the previous one. Hence the 5th element will be equal to a + 18b.Thus: a + 6b = 8 eq.1 a + 18b = 44 eq. 2Let's subtract the two equations - eq.2 -eq.1 we get 12 b = 44-8 = 36. Hence b = 3 and a = -10
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