Solve (2x^2 - 3x - 14)/(x^2 + 6x + 8) = -6/(x+3).

LHS: Factorise numerator and denominator, which gives:((2x - 7)(x + 2))/((x + 2)(x + 4))Cancel out (x + 2), gives:(2x - 7)/(x + 4)Multiply both sides by (x + 4)(x + 3) to cancel the denominators, gives:(2x - 7)(x + 3) = -6(x + 4)Expanding brackets:2x^2 - x - 21 = -6x - 24Make RHS = 0:2x^2 + 5x + 3 = 0Solve with factorisation/complete the square/quadratic formula:(2x + 3)(x + 1) = 0x = -2/3, -1

JL
Answered by Joseph L. Maths tutor

2903 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Show that (x + 4)(x + 5)(x + 6) can be written in the form ax3 + bx2 + cx + d where a, b, c and d are positive integers.


solve: 4x^2 + 6x - 4 > 0


A group of 55 pupils were asked if they owned a phone or a tablet.11 people are known to own both18 said they only owned a tablet34 said they owned at least a phoneA student is picked a random, what is the probability that the student doesn’t have a phone


How do you calculate the sum of all internal angles of a regular polygon?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning