Find the derivative of the function y = (2x + 12)/(1-x)
Using quotient rule, let u = 2x+12 and v = 1-x. Then we differentiate u and v separately, so u' = 2 and v' = -1. The formula for the quotient rule is: (vu' - uv')/v^2. Plugging in our values into this equation we get: vu'= 2-2x, uv' = -2x-12 and v^2 = (1-x)^2. Then vu' - uv' = 2 - 2x - (2x-12) = 2 -2x + 2x +12 = 14. So (vu' - uv')/v^2 = 14/(1-x)^2
MJ
Related Maths A Level answers
All answers ▸Solve the equation 3 sin^2 theta = 4 cos theta − 1 for 0 ≤ theta ≤ 360
Evaluate f'(1) for the function f(x) = (x^2 + 2)^5
The curve C has equation y=2x^2 -11x +13. (a) The point P has coordinates (2, – 1) and lies on C. Find the equation of the tangent to C at P.
How to differentiate using the chain rule