Find dy/dx when y = x^2(cos(x)).

y = x2(cos(x)) therefore we will need to use the product rule, 

dy/dx = u dv/dx + v du/dx

where u = x2 and v = cos(x)

du/dx = 2x and dv/dx = - sin(x), (don't forget the negative symbol when differentiating cosine)

dy/dx = x2(- sin(x)) + cos(x)(2x)

dy/dx = 2x(cos(x)) - x2(sin(x))

JS
Answered by Joseff S. Maths tutor

32134 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Express 9^3x + 1 in the form3^y ?


C4 June 2014 Q4: Water is flowing into a vase. When the depth of water is h cm, the volume of water V cm^3 is given by V=4πh(h+4). Water flows into the vase at a constant rate of 80π cm^3/s. Find the rate of change of the depth of water in cm/s, when h=6.


Integrate the following expression with respect to x by parts: (2*x)*sin(x)


Find the equation of the straight line that passes through the points (1,2) and (2,4)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning