A curve has an equation of y=2x^2 + 7x -8 . Find the co-ordinates of the turning point

Student will need to understand that the turning point will be a minimum as the curve is positiveStudent should complete the square:1) factorise out the 2: 2(x2 + 7/2 x) - 82) complete the square : 2[(x+7/4)2 - (7/4)2] -8 3) the student should square 7/4 to get: 2[(x+7/4)2 - 49/16] -84) multiply the 49/16 by 2: 2(x+7/4)2- 49/8 -84) 2(x+7/4)2 - 113/8 Therefore the co ordinates are (-7/4 , -113/8)

FH
Answered by Farah H. Maths tutor

3050 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the following simultaneous equation for x and y: 2x + 5y = 8, 4x + y = 7


A and B are two points. Point A has coordinates (–2, 4). Point B has coordinates (8, 9). C is the midpoint of the line segment AB. Find the coordinates of C


y is directly proportional to (d+2)^2, when d=5, y=147. d^2 is inversely proportional to x^2, when d=2, x=3. Find an equation for y in terms of x


how do i factorise a quadratic equation when the coefficient of x^2 is not 1?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences