A curve has an equation of y=2x^2 + 7x -8 . Find the co-ordinates of the turning point
Student will need to understand that the turning point will be a minimum as the curve is positiveStudent should complete the square:1) factorise out the 2: 2(x2 + 7/2 x) - 82) complete the square : 2[(x+7/4)2 - (7/4)2] -8 3) the student should square 7/4 to get: 2[(x+7/4)2 - 49/16] -84) multiply the 49/16 by 2: 2(x+7/4)2- 49/8 -84) 2(x+7/4)2 - 113/8 Therefore the co ordinates are (-7/4 , -113/8)
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