The function f(x)=x^2 -2x -24x^(1/2) has one stationary point. Find the value of x when f(x) is stationary, and hence determine the nature of this stationary point.
dy/dx = 2x - 2 -12x-1/2dy/dx = 02x - 2 - 12x-1/2 = 0x = 4 (stationary point)d2y/dx2= 2 + 6x-3/2when x=4, d2y/dx2= 11/411/4 > 0 therefore the point is a minimum
Related Maths A Level answers
All answers ▸What is the chain rule?
Find X log(x)=4 Base 10
Line AB, with equation: 3x + 2y - 1 = 0, intersects line CD, with equation 4x - 6y -10 = 0. Find the point, P, where the two lines intersect.
The quadratic equation 2x^2+ 6x+7 has roots a and b. Write down the value of a+b and the value of ab.