A and B are points on a circle, centre O. BC is a tangent to the circle. AOC is a straight line. Angle ABO = x°. Find the size of angle ACB, in terms of x. Give your answer in its simplest form. Give reasons for each stage of your working.

(This question is from the Edexcel Higher GCSE paper 2018) As BC is a tangent to the circle, we know that angle OBC must be a right angle (90 degrees)We also know that lines OA and OB are both the same length as they are radii of the circleThis means that angle ABO is the same size as angle BAO - they are both xAs angles in a triangle add up to 180 degrees, the equation we need is:ACB = 180 - 90 (from the right angle) - x - x and this can be simplified toACB = 90 - 2x

RT
Answered by Rachel T. Maths tutor

11568 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Find max point of y=-x^2-5x-10


How do I calculate the gradient of a non linear equation at a given point?


The line AB has equation 3x +5y = 7 . Find the gradient of AB.


Find the complex solutions for the following equation: -3x^2+4x+4=0


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning