Solve the following pair of simultaneous equations; 10x+4y=15, 2x+y=7

So, to solve these equations, you must choose the variable you want to work with, in this case let's go with y. Make sure that you write out every step of your working so it is easy to follow and minimises mistakes. As we are focusing on y, lets re-arrange the second equation to y=7-2x. Now we can just substitute this into the first equation: 10x+4(7-2x)=15. Now we are left with one variable which allows us to find out its value. Expanding the bracket it gives us: 10x+28-8x=15. Tidying it up gives us: 2x=-13, which gives us x=-13/2. Leave it in the fraction form rather than decimal as it is easier to work with. Now, we know the x value, we insert that back into the second equation: 2(-13/2) +y=7, -13+y=7, y=20. To check your answer is correct, put these values into first equation with x and y values: 10(-13/2)+4(20)=15, -65+80=15, 15=15.

JH

Related Maths GCSE answers

All answers ▸

How do you factorise quadratic equations by completing the square?


n is an integer greater than 1. Prove algebraically that n^2-2-(n-2)^2 is always an even number


How do I work out the measurement of an angle in a right-angle triangle?


There are 9 counters in a bag. 7 of the counters are green. 2 of the counters are blue. Ria takes at random two counters from the bag. Work out the probability that Ria takes one counter of each colour. You must show your working.