Solve the following pair of simultaneous equations; 10x+4y=15, 2x+y=7

So, to solve these equations, you must choose the variable you want to work with, in this case let's go with y. Make sure that you write out every step of your working so it is easy to follow and minimises mistakes. As we are focusing on y, lets re-arrange the second equation to y=7-2x. Now we can just substitute this into the first equation: 10x+4(7-2x)=15. Now we are left with one variable which allows us to find out its value. Expanding the bracket it gives us: 10x+28-8x=15. Tidying it up gives us: 2x=-13, which gives us x=-13/2. Leave it in the fraction form rather than decimal as it is easier to work with. Now, we know the x value, we insert that back into the second equation: 2(-13/2) +y=7, -13+y=7, y=20. To check your answer is correct, put these values into first equation with x and y values: 10(-13/2)+4(20)=15, -65+80=15, 15=15.

JH
Answered by Jung H. Maths tutor

3232 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve x^2+6x+1=0 by completing the square


Work out the value of n, the value of A & the value of B (question given below in correct subscript)


f:x-->2x^2+1 and g:x--> 2x/(x-1) where x is not equal to 1. express the composite function gf as simply as possible


The equation of the line L1 is y = 3x – 2 The equation of the line L2 is 3y – 9x + 5 = 0 Show that these two lines are parallel.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning