Solve the following simultaneous equations. x^2 + 2y = 9, y = x + 3

x^2 + 2y = 9y = x + 3
x^2 + 2y = 9x^2 + 2(x+3) = 9x^2 + 2x + 6 = 9x^2 + 2x - 3 = 0(x + 3)(x - 1) = 0x= -3, x = 1
when x = -3y = x + 3y = (-3) + 3y = 0
when x = 1y = x + 3y = (1) + 3y = 4

JF
Answered by John F. Maths tutor

2792 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve 7x + 6 > 1 + 2x


when given that y is 20% bigger than x, how can you express this as a ratio of y to x?


Solve these simultaneous equations: 2x + y = 7, and 3x - y = 8. Do so by 1) Eliminating an Unknown and 2) Substitution.


Find the values of a, b and c in the equation: (5x + 3)(ax + b) = 10x^2 + 11x + c.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning