Differentiate y=x^x with respect to x.
y=x^x, taking natural log of both sides
ln(y)=ln(x^x), using laws of logs
ln(y)=xln(x), using product rule and implicit differentiation
dy/dx 1/y=ln(x)+1
dy/dx=(ln(x)+1)y
dy/dx=(ln(x)+1)x^x
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