How can we determine stationary points by completing the square?

Suppose we have completed the square on y=ax^2+bx+c and attained y=a(x+p)^2+q, where a,b,c,p,q are real numbers with 'a' not equal to zero and p,q can be expressed in terms of a,b,c. For a>0 we have a minimum point, where x takes a value such that a(x+p)^2+q is smallest, giving x= -p and hence y=q. For a<0, we have a maximum point, where x takes a value such that a(x+p)^2+q is biggest, also giving x= -p and hence y=q. 

HY
Answered by Hayk Y. Maths tutor

14182 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

What does it mean to differentiate a function?


C and D are two events such that P(C) = 0.2, P(D) = 0.6 and P(C|D) = 0.3. Find P(D|C), P(C’ ∩ D’) & P(C’ ∩ D)


Differentiate y = (6x-13)^3 with respect to x


Find the roots of this equation: y=(8-x)lnx


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences