A car is travelling with a velocity of "0.5t^2+t+2" m/s at t=0 (where t is in seconds), find the acceleration of the car at a) t=0 b)t=2

Acceleration can be described as the 'rate of change of velocity' as it is simply how quickly the car is increasing/decreasing in velocity. Therefore as the velocity is described as an expression of t - time in seconds after a certain point - and you know differentiation finds the gradient function of a polynomial, and as gradient is the rate of change of the polynomial, you can simply differentiate the expression for velocity with respect to t to find the function for acceleration of the car (in terms of t = t + 1). Now simply plug the values of t=0 and t=2 to find the acceleration of the car at those values of t.a) Acceleration = 1 ms-2b) Acceleration = 3 ms-2

DE
Answered by Dominic E. Maths tutor

2866 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

The sum of the first K natural numbers is 300. Find the value of K.


Express 2/P(P-2) in Partial Fractions (C4)


How to prove that (from i=0 to n)Σi^2= (n/6)(n+1)(2n+1), by induction.


Do the following vector equations intersect? l = (1 + μ)i + (2 - μ)j + (2μ - 5)k, and m = 2λi + 3j + (2 + λ)k.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning