How do I work out the equation of a tangent line to a curve?

A tangent line to a point of a curve is the straight line which is parallel to the the curve at that point.The equation of any straight line has equation form : y-y_1 = m(x-x_1) where m is the gradient of the line and (x_1,y_1) is ANY point on the linetherefore all we need to do is:find a point on the tangent line. Suppose we want to the find the equation of the tangent line to a curve at the point x=5. Then substitute x=5 in the equation of the curve and we have a point on the line!Calculate the gradient (slope) of the tangentThis is calculated by differentiating the equation of our curve then substituting the x-coordinate at which we wish the work out the tangent equationsubstitute m and (x_1, y_1) into the straight line equation and rearrange.

Answered by Maths tutor

3818 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How can I differentiate x^2+2y=y^2+4 with respect to x?


Prove that 1+2+...+n = n(n+1)/2 for all integers n>0. (Hint: Use induction.)


the line L goes through the points A (3,1) and B(4,-2). Find the equation for L.


The finite region S is bounded by the y-axis, the x-axis, the line with equation x = ln4 and the curve with equation y = ex + 2e–x , (x is greater than/equal to 0). The region S is rotated through 2pi radians about the x-axis. Use integration to find the


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning