How do I work out the equation of a tangent line to a curve?

A tangent line to a point of a curve is the straight line which is parallel to the the curve at that point.The equation of any straight line has equation form : y-y_1 = m(x-x_1) where m is the gradient of the line and (x_1,y_1) is ANY point on the linetherefore all we need to do is:find a point on the tangent line. Suppose we want to the find the equation of the tangent line to a curve at the point x=5. Then substitute x=5 in the equation of the curve and we have a point on the line!Calculate the gradient (slope) of the tangentThis is calculated by differentiating the equation of our curve then substituting the x-coordinate at which we wish the work out the tangent equationsubstitute m and (x_1, y_1) into the straight line equation and rearrange.

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The equation of a line is y=3x – x^3 a) Find the coordinates of the stationary points in this curve, stating whether they are maximum or minimum points b) Find the gradient of a tangent to that curve at the point (2,4)


I did all the past papers but I still only achieved a C grade, what am I doing wrong?


Split 1/x^2-1 into partial fractions


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