How do I integrate sin^2(x)?
First, remember the compound angle formula for cosine:
cos(2x)=cos^2(x)-sin^2(x). Now use the identity sin^2(x)+cos^2(x)=1 to give:
cos(2x)=(1-sin^2(x))-sin^2(x)=1-2sin^2(x)
Rearranging this so we have sin^2(x)=1/2(1-cos(2x))
Replace this with the original integration and use the chain rule to get:
1/2(x-1/2sin(2x))+c
CD
Related Maths A Level answers
All answers ▸Show that: [sin(2a)] / [1+cos(2a)] = tan(a)
Express 4sin(x)+6cos(x) in terms of Rsin(x+a) where R and a are constants to be determined (a should be given in rad).
How would you find the coordinates of the intersections of a graph with the x and y axes, and the coordinates of any turning points?
ABCDEF