How do I solve a simultaneous equation?

You will be presented with two equations, both with two unknown values. For example:

8x-2y=19

and

3x=5+y

 

To begin, we are going to move both unknown terms in the second equation to the same side:

3x-y=5

 

Then, we are going to multiply this entire equation by 2, in order to have equal y values:

6x-2y=10

 

At this point, we will subtract the manipulated second equation to the first, so that we cancel out the y values:

2x=9

 

Now we can find the value of x by dividing by 2:

x=4.5

 

With this value of x, we can find the value of y through substitution. Putting our value for x into the first equation:

8(4.5)-2y=19

36-2y=19

36=19+2y

17=2y

8.5=y

 

Having shown this working, you can give the answer on your paper as follows:

x=4.5, y=8.5

 

Remember you will always need to show your working when doing this in an exam.

PC
Answered by Paul C. Maths tutor

5828 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Find an equation of the line which passes through the point (4,-7) and has slope 3.


Show that (x+1)(x+2)(x+3) can be written as ax^3+bx^2+cx+d


Solve equations 2x+y=9 and x+2y=6 to find x and y.


The equation of the line L1 is y=3x–2. The equation of the line L2 is 3y–9x+5=0. Show that these two lines are parallel.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning