Differentiate and then integrate: x^2 + 3x

To differentiate, the rule is to bring the power down to the front and multiply the expression, then take one off the value of the power, for example: d/dx(x²) = (2)x^2-1 = 2x, so the answer to the the question given is: (2)x^2-1 + (1)3x^1-1 = 2x + 3
To integrate, you first add one to the power, and then divide the expression by the new value of the power for example: integrate(x²) = x²⁺¹(1/3)So the answer to the question is: x²⁺¹(1/3) + 3x¹⁺¹(1/2) = (1/3)x³ + (1/2)x² + CRemember to add the constant of integration (C) and sometimes if we were to differentiate just a number, the expression would disappear and so we need to account for this in the integral.