Solve the simultaneous equations: y=x+1, x^2+y^2=13
We already have an expression for y, so we can substitute this in:x2+(x+1)2=x2+(x+1)(x+1) = x2+x2+2x+1=2x2+2x+1 and hence 2x2+2x+1=13 and so 2x2+2x-12=0Now look for common factors. Here we can take out a factor of 2 to get2(x2+x-6)=0And we can use method to factorise to 2(x-2)(x+3) = 0So setting expressions to 0 we have x=2 or x=-3.Substitute values back into expression for y to obtainy = x+1 = 2+1 = 3 or y = -3+1 = -2
LC
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