Solve 5x^2 = 10x + 4 Give your answers to 2 decimal places. [4 marks]

5x^2 = 10x + 4 5x^2 - 10x = 4 5x^2 - 10x - 4 = 0 ax^2 +bx +c = 0 x = (-b (+/-) ( b2 -4ac)1/2) /(2a) x = (--10 (+/-) ((-10)2- (4 x 5 x -4))1/2)/(2 x 5) x = (10 (+/-) (100 + 80)1/2)/10 x = (10 (+/-) (180)1/2 )/10 x = 2.341(...) and –0.341(...) x= 2.34 and –0.34 (to 2.d.p)

JT
Answered by JOSHUA T S. Maths tutor

5945 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Show (4+5/7) - (2+1/3) as a single mixed fraction.


Show x^2 + 8x +15 = 0 in the form of (x+b)^2 +c (complete the square) and then solve the equation


Work out the area of this triangle given the lengths of 1 sides (a) and 2 angles (A and B) using either the sine rule


The equation of the line L1 is y=3x–2. The equation of the line L2 is 3y–9x+5=0. Show that these two lines are parallel.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences