Find dy/dx, given that y=(3x+1)/(2x+1)

Since the equation for y is given in the format y=u/v, the use of the quotient rule is the easiest way to find the differential of this equation. The quotient rule states, (vu'-uv')/v^2 is equal to the differential of u/vIn this situation u=3x+1 and v=2x+1. The first step to take would be to differentiate the individual parts of the equation so, u'=3 and v'=2.These 4 values can then be put into the quotient rule in order to reach the result of the differential. dy/dx=(3(2x+1)-2(3x+1))/(2x+1)^2, which can be simplified down to dy/dx=1/(2x+1)^2

Answered by Maths tutor

4635 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Differentiate with respect to x: F(x)=(x^2+1)^2


Why is the derivative of 2^x not x*2^(x-1)?


Integrate the natural logarithm of x (ln x) with respect to x


How do I show two lines are skew?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences