Find dy/dx, given that y=(3x+1)/(2x+1)

Since the equation for y is given in the format y=u/v, the use of the quotient rule is the easiest way to find the differential of this equation. The quotient rule states, (vu'-uv')/v^2 is equal to the differential of u/vIn this situation u=3x+1 and v=2x+1. The first step to take would be to differentiate the individual parts of the equation so, u'=3 and v'=2.These 4 values can then be put into the quotient rule in order to reach the result of the differential. dy/dx=(3(2x+1)-2(3x+1))/(2x+1)^2, which can be simplified down to dy/dx=1/(2x+1)^2

Answered by Maths tutor

4883 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

A ball is thrown vertically upwards with a speed of 24.5m/s. For how long is the ball higher than 29.4m above its initial position? Take acceleration due to gravity to be 9.8m/s^2.


How and when do you use integration by parts?


How can you find out if two lines expressed in their vector form intersect?


Given that y = 3x(^2) + 6x(^1/3) + (2x(^3) - 7)/(3(sqrt(x))) when x > 0 find dy/dx


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences