find dy/dx when y=x^3 + sin2x

so this question is asking you to differentiate x3 + sin2xwe know that xn differentiates do nxn-1, so using that x3 will differentiate to 3x2we know that sinx differentiates to cosx and 2x differentiates to 2, so sin2x (by chain rule) differentiates to 2cos2xthen adding them, we get dy/dx = 3x2+2cos2x

Answered by Maths tutor

4446 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

What is a parametric equation?


Using methods of substitution solve the following simultaneous equations: y - 2x - 1 = 0 and 4x^2 + y^2 - 25 = 0


If f(x) = x^2 - 3x + 2, find f'(x) and f''(x)


By completing the square, find the values of x that satisfy x^4 -8x^2 +15 = 0


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning