find dy/dx when y=x^3 + sin2x

so this question is asking you to differentiate x³ + sin2xwe know that xⁿ differentiates do nx^n-1, so using that x³ will differentiate to 3x²we know that sinx differentiates to cosx and 2x differentiates to 2, so sin2x (by chain rule) differentiates to 2cos2xthen adding them, we get dy/dx = 3x²+2cos2x