Find the x values for stationary points in the curve y=3sin(2x) for 0<x<180

Firstly we differentiate the equation y=3sin(2x) w.r.t. x.By using the chain rule, we find the dy/dx=6cos(2x)Since a stationary point in the curve is a point where the gradient is 0, we can find them by finding the x values for when dy/dx=0.Therefore, 6cos(2x)=0cos(2x)=02x= cos-1(0) since cos-1(0)=90, 270 x=45, 135

Answered by Maths tutor

3468 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Differentiate the equation y = x^2 + 3x + 1 with respect to x.


Find a solution for the differential equation dy/dx=exp(-y)*sin2x which passes through the origin.


The volume of liquid in a container is given by v=(3h^2+4)^(3/2)-8, find dV/dh when h = 0.6


Solve the


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences