Work out the equation of the tangent at x = 3, knowing that f(x) =x^2
Currently, we know that:f(x) = x2To find the equation of the tangent you need the gradient and the y-value of the graph at x = 3So, you can differentiate f(x):f'(x) = 2xlet x = 3: f(x) = 9 f'(x) = 6the equation of the line is written by:y - y1 = m(x-x1)By substitution:y - 9 = 6(x - 3)y = 6x - 9 --> this is the answeri do have a laptop with a touch screen and a pen, so it is easy for me to write
AA
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