The equation of line L is y = 3x - 2 and the equation of line Q is 3y - 9x + 5 = 0, show these two lines are parallel

The basic equation of a line is I=the general form y = mx + c. Where c is a constant and m is the gradient of the lineFor lines to be parallel they must have the same gradient, then they will never crossThe gradient for line L is therefore 3, as this is the number in front of xBy rearranging the equation of line Q to fit the general form we find that:3y = 9x - 5y = 3x - (5/3)Therefore line Q also has the same gradient and is thus parallel

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Answered by Harry H. Maths tutor

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The area of a parallelogram is given by the equation 2(x)^2+7x-3=0, where x is the length of the base. Find: (a) The equation of the parallelogram in the form a(x+m)^2+n=0. (b) The value of x.


Rearrange to make p the subject. C + 5 p = a ( C – p )


Factorise fully 3*a^3*b +12*a^2*b^2 + 9*a^5*b^3


work out 2/15 x 15/22


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