Calculate the volume obtained when rotating the curve y=x^2 360 degrees around the x axis for 0<x<2

I haven't yet figured out how to write in proper mathematical notation on here, and my drawing pad is yet to arrive, so please forgive the formatFirst, the formula for the volume of revolution is V= pi * the integral of (y)^2 dxIn this case it means V = pi * integral (x^4)dx between 0<x<2integrating x^4 gives 0.2 x^5 as we reverse the process of bringing down the power and multiplying, henceV= pi * [0.2 x^5] between 0<x<2Substitute values givesV=pi*(0.22^5-0.20)V=pi0.232V=6.4*pior V=20.106....

Answered by Maths tutor

3215 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Simplify the following C4 question into it's simplest form: (x^4-4x^3+9x^2-17x+12)/(x^3-4x^2+4x)


How to differentiate 2x^5-4x^3+x^2 with respect to x


C4 June 2014 Q4: Water is flowing into a vase. When the depth of water is h cm, the volume of water V cm^3 is given by V=4πh(h+4). Water flows into the vase at a constant rate of 80π cm^3/s. Find the rate of change of the depth of water in cm/s, when h=6.


Find the gradient of y=x^2-6x-16 at the point where the curve crosses the x-axis


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning