Write x^2 + 6x - 10 in the form ((x+a)^2)+b?

To find the value of a divide the coeffecient of x. Here this would be 6/2 which = 3. If we were to expand (x + 3)^2 + b this would give us:x^2 + 3x +3x + 3^2 +b which simplifies to x^2 + 6x + 3^2 + b. If we compare the coeffecients of this with the given quadratic, we can see the constant term is 3^2 + b = - 10If we rearrange this we can see b = -19Therefore x^2 + 6x - 10 in the form ((x+a)^2)+b is (x + 3)^2 - 19.The b is always equal to a^2 - [constant term of the quadratic].

GG
Answered by Gunalini G. Maths tutor

12873 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

The first floor of an ancient japanese tower has 150 steps. Each floor above has 5 fewer floors than the previous. So, the second floor has 145 steps, the third 140 etc. How many floors does the tower have if the final floor has 30 steps leading to it.


Solve x^2 - 9 = 4x + 12


The equation of the regression line of y (retail price, £) on x (number of pages) for a set of books is y = 0.02x + 1.35. How can I use this equation?


There are 3 red beads and 1 blue bead in a jar. A bead is taken at random from the jar. what is the probability that the bead is blue?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences