Given y=(1+x^3)^0.5, find dy/dx.

In order to solve this question, we need to use the chain rule when differentiating. The chain rule formula is dy/dx= (dy/du)(du/dx). Let u=1+x3Differentiating with respect to x gives du/dx=3x2We now have y=u0.5Differentiating with respect to u gives dy/du=0.5u-0.5=0.5(1+x3)-0.5Therefore dy/dx= (dy/du)(du/dx)= 0.5(1+x3)-0.5*(3x2)= 1.5x2*(1+x3)-0.5

RM
Answered by Rebecca M. Maths tutor

6158 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

A curve with equation y = f(x) passes through the point (4,25). Given that f'(x) = (3/8)*x^2 - 10x^(-1/2) + 1, find f(x).


What is the gradient of the function y=x^3 at the point x=1?


Find the coordinate of the turning point of the curve y = x^2 - 10x + 7, by completing the square


A block mass m lies on an incline rough plane, with coefficient of friction µ. The angle of the block is increased slowly, calculate the maximum angle of the slope that can be achieved without the block slipping.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning