Solve the following simultaneous equations: 2x - 3y = 16, x + 2y = -6

First we label the two equations as (1) and (2):2x - 3y = 16 (1)x + 2y = -6 (2)We want both equations to have the same number before one of the variables so the easiest way is to multiply equation (2) by two to give an equation we'll label (3):2x + 4y = -6 (3)Now we can do (1) - (3) to cancel out the value of x: (1)-(3) : -7y = 28, which can be solved to give y = -4. Now to get the value of x we substitute this y into one of the original equations, for example (2), giving: x - 8 = -6 which can be solved to give x = 2.So our final answer is x = 2, y = -4.

TD
Answered by Tutor401319 D. Maths tutor

4565 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

A plane flew from Frankfurt to Hong Kong. The flight time was 10hours 45minutes. The average speed was 852km/h. Work out the distance the plane flew.


Solve the quadratic inequality x^2+x-6>/= 0.


How do you expand brackets?


There are 892 litres of oil in Mr Aston’s oil tank. He uses 18.7 litres of oil each day. Estimate the number of days it will take him to use all the oil in the tank.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning