Solve the following simultaneous equations: 2x-3y=16 x+2y=-6

First, label the two equations as follows:2x-3y=16 --> [1]x+2y=-6 --> [2]To obtain the same x value for both equations, [2]2: 2x+4y=-12 --> [3]Then, to eliminate the x values from both equations, [1]-[3]: -7y=28, therefore y=-4To obtain the x value, substitute the calculated y value into either equation (could do the other to double check) as follows:Into equation [1]: 2x-3(-4)=16, therefore 2x=4, so x=2 (Check with equation [2]: x+2*(-4)=-6, therefore x=2)Alternative method would be to match the two y values to make it 6y in both equations, but given that both equations need to be altered for this, it is much more inefficient and therefore the described method is much more desirable. Answer: x=2, y=-4

MH
Answered by Masaki H. Maths tutor

3485 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Find the solutions to this quadratic equation: 0 = 2x^2 - 5x - 3


Solve the simultaneous equations 3x=2y and 2xy=12


There are 35 people in a group. x(x+1) of them have a blue car, 5x of them have a red car, 4 have a blue and a red car and 4x-8 do not have car. Work out the probability that a person who has a blue car, has a red car as well.


expand and simplify (x+1)(x-1)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning