Solve the following simultaneous equations: 3x + y = 11, 2x + y = 8

first: look at the 2 equations and see if there are any matching coefficients. eg the same number before x or y in both of the equations. in these examples both y values have the coefficient 1. second: either add or subtract the 2 equations to remove the y values. in this case need to do equation 1 - equation 2 in order for y to equal 0. so (3x + y = 11) - (2x +y = 8) = x = 3 - this is the x value of the equations third: find the y value by substituting the known x value (3) into one of the simultaneous equations = 2(3) + y = 8 6 +y = 8 y = 2 - this is the y value fourth: you can check you have the right values by substituting them into one of the equations and seeing if it works. eg 3(3) + 2 = 11 9+2 = 11 11 = 11

RS

Related Maths GCSE answers

All answers ▸

Simplify √(4x^8).


Bob lives 2km away from Alice and the school is 1km away from Bob. Alice sets off to meet Bob at 8am and she meets him at 8:15 and they carry on walking at the same pace. School starts at 8:20. Do they get to school on time? How early/late are they?


Sarah plans to paint a rectangular wall of dimensions 8.7m x 2.3m. A tin of paint costs £16.10 and covers 6 metres squared. Sarah has a budget of £56, can she afford to paint the wall? Explain your reasoning.


Given that x^2+10x+3 can be written in the form (x+a)^2+b, find the values of a and b.