Prove that the difference between the squares of two consecutive odd numbers is a multiple of 8.

(2n+3)2-(2n+1)2=(4n2+12n+9)-(4n2+4n+1)=8n+8= 8(n+1)Hence a multiple of 8

DB
Answered by Daniel B. Maths tutor

31235 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve: 6x + 3 = 3x + 9


The sides of a rectangle are x and (x+2), where x>0 the area of the rectangle is 8, what is the value of x?


How do you solve the #EdexcelMaths question?


Solve simultaneously, 2x-3y=16 and x+2y=-6


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning